Jawabanmu

2014-03-23T21:34:52+07:00
Q = 12600 J 
c = 4.200 j/kgC
m = 150 gr = 0,15 kg
t1 = 10 derajat
t2=....?
delta t = suhu akhir -suhu awal = t2 - t1

Q = m.c.delta t
12.600 = 0,15 . 4200 . (t2 - 10)
12600 = 630 ( t2 - 10 )
t2 - 10 = 20
t2 = 20 + 10
t2 = 30 derajat celcius