Jawabanmu

2014-03-22T12:17:27+07:00
Q = 84 kj = 84000
m = 500 g = 0.5 kg
t1 = 20 C
kalor jenis = 4200J/(Kg.K)
t2 = ?

Δt = Q/m . kalor jenis
( t2 - t1 ) =  8400/ 0,5 . 4200
( t2 - 20) = 40 
t2 = 40+20
t2 = 60 derajat celcius

6 2 6
2014-03-22T12:19:50+07:00
Dik:
Q = 84 KJ = 84.000 J
m = 500 gr = 0,5 kg
c = 4.200 J/Kg C
T1 = 20 C

dit: T2

jawab :
ΔT = Q / m . c
(T2-T1) = 84000 / 0,5 . 4200
(T2 - 20) = 40
T2 = 40 + 20
T2 = 60 C
2 2 2