Jawabanmu

2014-03-19T09:57:28+07:00
Dik : 9,8 gram H2SO4, Mr = 2 + 32 + 4 = 38, vol = 250 ml

Mol = gr/Mr = 9,8/38 = 0,257
Mb = mol / vol = 0,257/0,25 = 0,002 = 2x10pangkat-3

H2SO4 --> 2H+ + SO4 -2 ( + sama -2 nya itu pangkat ya)
[OH-] = b x Mb
         = 1 x 2x10pangkat-3 = 2x10pangkat-3
POH = -log 2x10pangkat-3
         =3-log2
PH = PKW-POH = 14 - (3-log2)
      =11+log2



2014-03-19T10:09:20+07:00
M = 9,8 gr , 250 mL  H_{2}  SO_{4} ,
Ar H=1, S=32, O=16 , maka Mr  H_{2}  SO_{4}  = 2 *Ar H + 1 * Ar S + 4 * Ar O = 2+32+64 = 98

M= \frac{n}{V} =  \frac{ \frac{m}{Mr} }{V} = \frac{ \frac{9,8}{98} }{250} = \frac{01}{250} = 0,0004 =4* 10^{-4}

[ H^{+} ] =  M_{a} * a4*  10^{-4} * 2 8* 10^{-4}

pH = - log [H] = - log 8*10^{-4} = 4 - log 8 = 4 - 0,9 =3,1