Jawabanmu

2014-01-14T08:20:49+07:00
Ax2 (baca pangkat2) +bx +c = y

A (0.3)
ax2 + bx + c = y
3 = y
B (2,-5)
ax2 + bx + c = y
4a + 2b + 3 = -5
4a + 2b = -8
C (-1, 13)
ax2 + bx + c = y
-a -b +3 = 13
-a -b = 10

4a + 2b = -8
-a -b = 10 (dikali 2)
menjadi
4a + 2b = -8
-2a -2b = 20
ditambahkan menjadi
2a = 12
a = 6

-a -b = 10
-6 -b = 10
-b = 16
b = -16