Jawabanmu

2014-03-17T19:33:31+07:00
x² + y² + 6x - 4y - 7 = 0
(x+3)
² - 9 + (x-4)² - 4 - 7 = 0
(x+3)² + (x-4)² = 20
r = √20

tegak lurus berarti m' = -1/m
m' = -(1/-2)
m' = 1/2

persamaan garis
y-b=m(x-a)+r \sqrt{m^2+1} atau y-b=m(x-a)-r \sqrt{m^2+1}
y-4=m(x+3)+ \sqrt{20}  \sqrt{ (\frac{1}{2}) ^2+1}
y-4=m(x+3)+ \sqrt{25}
y-4=m(x+3)+5
y-4= \frac{1}{2} (x+3)+5
y= \frac{1}{2}x+ \frac{21}{2}
2y=x+21 atau 2y=x+11

CMIIW :3
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