Jawabanmu

2014-01-12T21:43:35+07:00
PH = 1 maka [H+] = 10^-1 = 0,1 M 
jml mol H+ pd larutan A = 0,1 . 100ml = 10 mmol

pH = 2 maka [H+] = 10^-2 = 0,01 M 
jml mol H+ pd lar. B = 0,01 . 100ml = 1 mmol

[H+] = total n H+/ total V = (10+1)mmol/(100+100)ml = 11/200 M = 0,055 M
pH = -log 0,055 = 1,23