Jawabanmu

2015-06-17T00:16:58+07:00
PH=6= buffer asam
[H+] = 10^-6

10^-6 = 10^-5 . mol asam/mol basa konjugasi
10^-1 = mol asam/mol basa konjugasi
mol basa konjugasi = 10 mol asam

vol total = 150ml
anggap vol CH3COOH=x


CH3COOH + NaOH => CH3COONa + H2O
0,1x              15-0,1x
15-0,1x          15-0,1x    15-0,1x
0,2x-15            -            15-0,1x

0,2x-15/15-0,1x=0,1
0,2x-15=1,5-0,01x
0,21x=16,5
x=78,57 ml
maka vol NaOH = 71,43ml

tolong di cek lagi