Jawabanmu

2014-03-12T19:47:48+07:00
113 F = ... C
5/9 (t-32) = 5/9 (113-32) = 45 C
40 C = ... R
4/5t = 4/5 dikali 50 = 40 R
40 R = ... K 
5/4t + 273 = 5/4 dikali 40 + 273 = 313 K 

2014-03-12T19:53:41+07:00
113f=5/9 ×113 -32=5/9×81=45°c 113°f=4/9×113-32=4/9×81=32°r 113°f=5/9×113+32-273=5/9×-241=301,25