Jawabanmu

2014-03-12T19:00:57+07:00
Sin 15 =  \frac{p}{1}  \frac{y}{r}

x =  \sqrt{r^{2}- y^{2}  }
   =  \sqrt{1^{2}- p^{2}  }

tan 15 =  \frac{y}{x}  \frac{p}{ \sqrt{1- p^{2} } }
1 3 1