Jawabanmu

2014-03-11T20:46:28+07:00
NaCN->Na+ + CN- 
0,1M 0,1M 
CN- + H20 -> HCN + OH-
 

[OH-]= akar kw/ka x [A-] 
=akar 10^-14/6,2 10^-10 x 0,1 
= akar 0,16 10^-5 
=akar 16 10^-6 
=4x10^-3 

pOH=3-log 4 
pH=14-(3-log4)= 11+log 4
pH = 11 + 0,602
pH = 11,602