Jawabanmu

2014-03-09T21:11:53+07:00
X^2-(m+3)x+(3m+1)

karena satu akar real jadi d=0

b^2-4ac=0
(-m-3)^2-4(1)(3m+1)=0
m^2+6m+9-12m-4=0
m^2-6m+5=0
(m-5)(m-1)
m=5
m=1
2014-03-09T21:25:31+07:00
D=b² - 4ac
  =(m + 3)² - 4(1) (3m + 1)
  =m² + 6m + 9 - 12m - 4
  =m² -6m - 5