Jawabanmu

2014-03-09T17:52:05+07:00
(2x-1)+(2x-2)....=600
berarti deret aritmatika
b=(2x-2)-(2x-1)=-1
U1=2x-1
U99=2x-99
S99=99/2((2x-1)+(2x-99))
600=99/2(4x-100)
400/33=4x-100
3700/33=4x
x=28,0303=28