Jawabanmu

2014-03-09T09:44:37+07:00
F^-1(x-1)= \frac{2x-3}{x+4}

sekarang kita cari f^-1(x) dengan cara memasuka inverse dari (x-1)
f^-1(x)= (2(x+1)-3)/((x+1)+4)
=(2x-1)/(x+5)
f(x)= (-5x-1)/(x-2)

g^-1(x)=((x-2)-2)/((x-2)+1)
=(x-4)/(x-1)
g(x)=(x-4)/(x-1)

(gof)(x)= ((-5x-1)-4)/((x-2)-1)
=(-5x-5)/(x-3)
=(-5(x+1)/(x-3)

(gof)(2x+3)=(-5((2x+3)+1))/((2x+3)-3)
=(-5(2x+4))/(2x)
=(-10x-20)/2x
=(-5x-10)/x