Jawabanmu

2014-03-07T23:56:30+07:00
AB=24

kita cari tinggi setigia

t^2=AC^2-(AB/2)^2
t^2=256
t=16 cm

L=1/2 at
=1/2 24 16
=192 cm^2

K=AB+AC+BC
=24+20+20
=64 cm

r=L/(K/2)
=192/32
=6 cm


2014-03-07T23:59:20+07:00
R=L/S
L=luas lingkaran
S=1/2 keliling lingkara
t=√20²-12²=√400-144=√256=16
L=24×16÷2=192
S=1/2(20+20+24)=32
r=L/S=192/32=6 cm

smg membantu.....:)