Jawabanmu

2014-03-04T11:14:54+07:00
(NH4)2 SO4 0.05 M dengan kb NH3 = 1.8*10^{-5}
OH⁻ = √Kb.Mb
=√10⁻².1.8.10⁻⁵
=√1.8⁻9
=√1.8⁻⁴,⁵

POH = - log OH⁻
     = - log 1,8.10⁻⁴,⁵
     =4.5+log 8
PH = 14 - POH
     = 14-
4.5+log 8
     = 9,5 +log 8
3 1 3
2014-03-04T14:31:06+07:00
(NH4)2 SO4 0.05 M dengan kb NH3 = 1.8*10^{-5}
OH⁻ = √Kb.Mb
=√10⁻².1.8.10⁻⁵
=√1.8⁻9
=√1.8⁻⁴,⁵

POH = - log OH⁻
     = - log 1,8.10⁻⁴,⁵
     =4.5+log 8
PH = 14 - POH
     = 14-
 4.5+log 8
     = 9,5 +log 8