Jawabanmu

2014-09-13T14:19:53+07:00
Garis A ⇒ P = (5, -4)
garis B ⇒ R = (5, -3) dan S = (1, -1)
Garis A tegak lurus garis B
mA x mB = -1
mB = (y2-y1) / (x2-x1)
mB = (-1 - (-3)) / (1 - 5)
mB = 2 / (-4)
mB = - 1/2

mA = -1 / mB = -1 / (-1/2) = 2

persamaan garis yang melalui titik (5, -4)
y - y1 = m(x - x1)
y - (-4) = 2 (x - 1)
y + 4 = 2x - 2
y = 2x - 6