Jawabanmu

2014-03-02T22:47:46+07:00
4sin4xcos6x kita jabarkan menjadi 

2 * (2cos6xsin4x) = 2 *(sin 10x-sin2x)
=2sin10x-2sin2x

integral = (-2*1/10cos10x+2*1/2cos2x)
= -1/5cos10x+cos2x
= (5 cos 2x - cos 10x)/5