Jawabanmu

2014-09-12T00:00:16+07:00
*2px^ + 2qxy + 3pxy +3qy^2=rx^2 + 23xy + 12 y^2
maka
*3qy^2=12y^2
3q=12
q=12/3=4
*2qxy + 3pxy =23xy
2q +3p = 23
2(4) + 3p = 23
8 + 3p = 23
3p =23-8
3p = 15
p = 15/3=5

2px^2 =rx^2
2p = r
2(5)= r
r=10
jadi nilai r = 10