Jawabanmu

2014-03-02T13:09:17+07:00
X^2+2x=0
x(x+2)=0
x= 0
x= -2

3x^2+20x+25=0
(3x+5) (x+5)=0
x= -5/3
x= -5

2x^2+2x-6=0
a= 2
b= 2
c= -6
x1= (-b+akar (b^2-4ac))/2a
x2= (-b-akar (b^2-4ac))/2a

b^2-4ac= 2^2-4*2*(-6)= 52

x1=1,3
x2=-2,3

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