Jawabanmu

2014-09-10T17:28:29+07:00
2log3 . 3log5 = 2log 5 = a . b =ab

 30_{log150} =  30_{log(30 x 5)}= 30x_{log 30}+ \frac{1}{ 5_{log 30}}= 1+  \frac{1}{ 5_{log30} }

1+ \frac{2log5}{2log30}

1+   \frac{ab}{2log(5 . 2. 3)} = 1+ \frac{ab}{ab+1 + 2log3}=1+ \frac{ab}{ab+1+b}

 100_{log 50} = 100_{log(100/2)}=  100_{log 100} -  100_{log2}

1 -  \frac{2log2}{2log100} =1 -  \frac{1}{2log(4 .25)} = 1-  \frac{1}{2log4+ 2log5}=1- \frac{1}{2+ab}
oiya lupa. dibuat dalam bentuk a dan b. a = ²log3 dan b = ³log5