Jawabanmu

2014-03-01T01:56:28+07:00
Soal no.1 kuadran 1 x = 60° + k*360° x = 60° ( utk k=0 ) kuadran 2 x = (180° - 60°) + k*360° x = 120° (utk k=0) Jadi hp = { 60° , 120°} soal no.2 2 cos 3x = √3 kuadran 1 cos 3x = √3/2 3x = 30° + k*360° x = 10° + k*120° x = 10° ( utk k=0) x = 130° (utk k=1) x = 250° (utk k=2) kuadran 4 cos 3x = √3/2 3x = (360°-30°) + k*360° x = 110° + k*120° x = 110° (utk k=0) x = 230° (utk k=1) jadi hp={10°, 110°, 130°, 230°, 250°}