Jawabanmu

2014-09-09T11:19:01+07:00
 2_{log \frac{1}{a} } =4/5   dan  8_{log b}=4   dan  a_{log \frac{1}{ b^{3}} } ;??

 2_{log \frac{1}{a} } =4/5 =>2loga=-4/5

alog2= - 5/4

 2^{3}log(b^{3})(^{1/3})=2log b^{1/3}=4


..alog 2 . 2log b^{1/3}=alogb^{1/3}=- 4/5 . 4 = -5 ..

1/3. alob=-5  .... alog b= - 15

a_{log \frac{1}{ b^{3}} }=a_{log  b^{-3}} }

= - 3 alogb = -3 x -15 =45