Jawabanmu

2014-09-08T20:13:55+07:00
(2x+3y)(px+qy) = rx^2+23xy+12y^2
2px^2+2qxy+3pxy+3qy^2 = rx^2+23xy+12y^2
(2p)x^2 + (2q+3p)xy + (3q) y^2 = r x^2 +23xy + 12y^2

3q=12
q=4

2q+3p=23
8+3p=23
3p=15
p=5

r=2p=2*5
r=10
5 3 5
2014-09-08T20:17:29+07:00
(2x+3y)(px+qy) = r² + 23xy + 12y²
2px²+2qxy+3pxy+3qy²= rx² + 23xy + 12y²
2px²+2qxy+3pxy+12y²= rx² + 23xy + 12y²
2px²+8xy+3pxy+12y²= rx² + 23xy + 12y²
2px²+8xy+15xy+12y²= rx² + 23xy + 12y²
10x²+8xy+15xy+12y²= rx² + 23xy + 12y²

q=4
p=5
r=5
6 3 6