Jawabanmu

2014-02-26T20:38:14+07:00
H3PO4 --> 3H^+    +    PO4^3- 
 0.04         (0.04x3)
                   0.12
[H^+] = 1.2x10^-1
pH = -log1.2x10^-1
     = 1 - log1.2
     = 1 - 0.07
     = 0.93