(1+1per2)(1+1per3)(1+per4)(1+per5).....(1+1perN)=11
A.berapakah nilai N?
B.sederhanakan bilangan yg didalam kurung.
C.amati pola perkalian beberapa bilangan awal.
D.dengan mengamati ,tentukan nilai N yg memenuhi persamaan diatas.

1

Jawabanmu

2014-09-07T19:06:55+07:00
(1+ \frac{1}{2} )(1+ \frac{1}{3} )(1+ \frac{1}{4} )...........(1+ \frac{1}{n} )=11

( \frac{2+1}{2})( \frac{3+1}{3})( \frac{4+1}{4}) ...............  ( \frac{n+1}{n})=11

(3 .4 .5. 6 ..........n) .  (n+1)  = 11 . 2. (3 .4 .5 ......... n)

n+1 = 11 . 2  <====> n = 22 -1 =20