Jawabanmu

2014-09-07T08:51:07+07:00
Integral cos (ax+b) = 1/a sin (ax+b) + c
jadi integral cos (3x+1) = 1/3 sin (3x+1) + c

1/cos x= cos^-1 x
integral cos^n x= 1/n+1 cos^n+1 x +c
jadi integral cos^-1 x = 1/(-1+1) cos^(-1+1) x+c
= 1/0 cos^0 x +c
= cos x+c