Pleasee di jawab yang benarr yaa!
Dua buah benda masing masing bermuatan -8 x 10'-9(10Pangkat-9) C dan +6 x 10'-9 C berada pada jarak 4cm satu sama lain.jika k=9x10'-9Nm2C-2, maka tentukan besar gaya tarik kedua benda tersebut?

2

Jawabanmu

2014-09-06T23:40:16+07:00
Diket : q1 = -8x10’-9 C
             q2 = 6x10’-9 C
              r = 4 cm = 0,04 m = 4x10’-2
             k = 9x10’-9 Nm2/C2
Ditanya : F?
Jwb : F = k.q1.q2/r’2
= 9x10’-9Nm2/C2 . -8x10’-9 C . 6x10’-9 C / (4x10’-2 m)’2
= 9x10’-9Nm2/C2 . -48x10’-18 C2 / 16x10’-4 m2  * C2 & m2 dicoret & -48 : 16
= 9x10’-9N . -3x10’-14
= -27x10’-23N


2014-09-07T09:43:41+07:00
Follow the arrow and  press this in your scientific calculator: 9 ⇒ EXP ⇒ (-)9 (NEGATIVESIGN) ⇒ X(multiply) ⇒-8⇒EXP⇒(-) (negative sign)⇒9⇒X(multiply)⇒6⇒EXP⇒ (-) this form (negative sign in your calculator)⇒9 ⇒ ÷ ⇒4⇒EXP⇒ (-) (negative sign in your calculator)⇒2⇒ and enter.

my answer : -2.7 x  10^{-22}

follow the arrow and  press this in your scientific calculator: 9 ⇒ EXP ⇒ 9(POSITIVE) ⇒ X(multiply) ⇒-8⇒EXP⇒(-) (negative sign)⇒9⇒X(multiply)⇒6⇒EXP⇒ (-) this form (negative sign in your calculator)⇒9 ⇒ ÷ ⇒4⇒EXP⇒ (-) (negative sign in your calculator)⇒2⇒ and enter.
my answer: -2.7 x  10^{-4}

take note the underline :) because this is the main use 9 x 10 x^{9} not negative so i solve for postive too in case.