segitiga ABC sebangun dengan segitiga DEC
DE~AB
CE~CB
CD~CA
jadii...
cari DC dulu dgn Phitagoras,
DC=10 cm
Lalu cari CB,
CB/CE=AC/DC
CB/8=15/10
10CB=120
CB=12cm
maka BD=
CB-CD= 12 -10 = 2cm
trims ea
ok sama"

Jawabanmu

2014-09-06T18:44:51+07:00
DE =6 cm
CE = 8 cm
AC = 15 cm
BD = ?
  AE = (AC - CE) = 15 - 8 = 7 cm
  DC =  \sqrt{DE^2 + CE^2}  \\ = \sqrt{6^2 + 8^2}    \\ = \sqrt{36+64}  \\ = \sqrt{100}  \\ =10 c,
  BD = AC - DE = 8-6 =2 (a)

 
2014-09-06T18:54:24+07:00
De=6
ce=8
dc=10
ac=dc
15=10
=3:2
bc=ec
10 + x : 8
10+x = 8/2*3
10+x = 12
x = 2 (a)