Jawabanmu

Jawaban paling cerdas!
2014-09-03T18:46:18+07:00
1)  1 + 3a² = 10a²
    -10a² + 3a + 1= 0
      (-5a - 1) (2a - 1) = 0
      \left \ {{-5a - 1=0} \atop {a =- \frac{1}{5}   \right  ∨   \left \ {{2a - 1=0} \atop {a = \frac{1}{2} }} \right.
 
 2)  3p² - 10p + 8 = 0
       (P - 2) (3P - 4) = 0
        \left \ {{p - 2=0} \atop {p = 0}} \right.  ∨   \left \ {{3p - 4 = 0} \atop {p =  \frac{4}{3} }} \right.

3)   2m² + 5m - 3 = 0
      (2m - 1) (m - 3) = 0
      \left \ {{2m - 1 = 0} \atop {m =  \frac{1}{2} }} \right.  ∨   \left \ {{m - 3 = 0} \atop {m = 3}} \right.


bkan 1 - 3a = 10a kuadrat ?
sudah bner jwbnnya tuh ????
blm tau jg sih hehe tp makasih banyak ya :)
oke siip
ya