Jawabanmu

2014-09-03T14:17:57+07:00
(2x+3y)(Px+Qy) = (rx^2+23xy+12y^2)
2Px^2+3Pxy+2Qxy+3Qy^2 = (rx^2+23xy+12y^2)
2Px^2+xy(3P+2Q)+3Qy^2 = (rx^2+23xy+12y^2)

Maka:
3Q = 12
Q = 4

3P+2Q = 23
3P + 2.4 = 23
3P = 23-8
3P = 15
P = 5

Daan...
2P = r
2.5 = r
r = 10

it's done, and easy Sekar...



makasih ya kak
sama2, semangat belajar!!