Jawabanmu

2014-02-22T14:29:29+07:00
H(x + 2) = x² + 2x
h(x) =  (x - 2)² + 2(x - 2)
h(x) = x² - 4x + 4 + 2x - 4
h(x) = x² - 4x + 2x + 4 - 4
h(x) = x² - 2x 
1 5 1
2014-02-22T14:41:49+07:00
2. pH = 4 ---> [H+] = 1 x 10^-4 [H+] = derajat ionisasi x M asam 10^-4 = 0,005 x M asam M asam = 0,02 M [H+] = √ Ka x M asam 10^-4 = √ Ka x 0,02 (10^-4)^2 = Ka x 0,02 .. 10^-8 = Ka x 0,02 Ka = 5 x 10^-7