Dik : f(x) = 2x+3 dan g(x) = x-2 / x+3 .jika (f°g) (a) = 0 , tentukan nilai a

1
f(x)=2x+3, g(x)=x-2/x+3, (f bundaran g) (a)=0
a=?
(fbundaran g)= f (g(x)) = f ( x-2/x+3) = 2. (x-2/x+3) + 3 = 2x-4/ x+3 + 3 = 5x+5/x+3

(f bundaran g) (x) = 5x+5/x+3 =0
= 5x+5= 0/x+3
= 5x+5 = 0
= 5x = -5
= x = -1
mungkin :)
Komentar sudah dihapus

Jawabanmu

Jawaban paling cerdas!
2014-02-21T20:05:35+07:00
F(g(a))=0 f(a-2: a+3)=0 2(a-2/a+3)+3 2a-4/a+3 =0 2a=4 maka a= 2
1 5 1