Jawabanmu

2014-09-01T09:47:33+07:00
1.a=13,b=3, t=5,luas = (a+b)/2.t=(13+3)/2.5= 8.5=40satuan
b. Luas segitiga 1= 1/2.4,5.6=13,5
luas segitiga 2=1/2.5.3,75=9,375
2014-09-01T10:32:08+07:00
Y=2x+3
batas kurvanya 0-5
luasnya =integral0-5(2x+3)
=[x^2+3x]0-5
=[5^2+3(5)]-[0^2+3(0)]
=25+15
=40 satuan