Jawabanmu

2013-12-24T07:13:49+07:00
1.a. jika dsubstitusi x=1, menghasilkan 0/0, maka harus dturunkan pembilang penyebut
f'(x)= \frac{3x^2-8x+3}{3x^2-13}= \frac{3.1^2-8.1+3}{3.1^2-13}=  \frac{3-8+3}{3-13}= \frac{-2}{-10}= \frac{1}{5}

1.b.
substitusi x=2
 \frac{2^3-4.2^2+3.2}{2^3-13.2+12}= \frac{8-16+6}{8-26+12}= \frac{-2}{-6}=\frac{1}{3}

1.c
substitusi x=3
 \frac{3^3-4.3^2+3.3}{3^3-13.3+12}= \frac{27-36+9}{27-39+12}= \frac{0}{0} 
karena 0/0 diturunkan dlu
f'(x)= \frac{3x^2-8x+3}{3x^2-13}= \frac{3.3^2-8.3+3}{3.3^2-13}= \frac{27-24+3}{27-13}= \frac{6}{14}= \frac{3}{7}
2 4 2