Jawabanmu

2014-08-30T07:58:38+07:00
 (\frac{3p^{2}q^{2}}{r^{4}}) ^{-1}  *  \frac{p^{6}}{r^{-3}} =

 (\frac{r^{4}}{3p^{2}q^{2}}) ^{1}  *  p^{6}r^{3} =

 \frac{p^{4}r^{7}}{3q^{2}}
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 \sqrt{27} + 3 \sqrt{243}  -  \sqrt{81}  -  \sqrt{225} =

 \sqrt{9*3} + 3 \sqrt{81*3}  -  9  -  15 =

 3\sqrt{3} + 3*9 \sqrt{3}  -  24 =

 3\sqrt{3} + 27 \sqrt{3}  -  24 =

30 \sqrt{3}  -  24

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