Jawabanmu

2014-02-18T22:08:37+07:00
H+ = akar Ka . HA
jadi pH = 3
mungkin seperti itu
diperjelas : H+=(ka.M)^1/2 = (10^-5.10^-1)1/2 = (10^-6)^1/2 = 10^-3, pH=-log H+ pH=-log 10^-3 pH=3
2014-02-19T07:03:24+07:00
H+=(ka.M)^1/2 = (10^-5.10^-1)1/2 = (10^-6)^1/2 = 10^-3, pH=-log H+ pH=-log 10^-3 pH=3