Jawabanmu

2014-08-26T18:45:12+07:00
X³+2x²+3x+6 = (x-1) (ax²+bx+c) + d
                   = ax³ + bx² + cx - ax² - bx - c + d
                   = ax³ + (b-a)x² + (c-b)x - c + d

a = 1

b-a = 2
b-1 = 2
b = 2+1
b = 3

c-b = 3
c-3 = 3
c = 3+3
c = 6

-c+d = 6
-6+d = 6
d = 6+6
d = 12

Hasil bagi : ax² + bx + c => x² + 3x + 6
Sisa: d => 12