Jawabanmu

2014-02-16T05:52:34+07:00
Hidrolisis...

[OH^-] = AKAR Kw.M/Ka = akar 10^-14 . 1/ 3,3x10^-4 = akar 0,303x10^-10 = 0,55x10^5
maka Poh= - log OH^-
             = - Log 5,5x10^-4
             = 4-log 5,5
PH=14-Poh
     = 14 - (4-log 5,5)
     =10 + log 5,5