Jawabanmu

2014-02-14T15:38:57+07:00
24000 = M.C.ΔT
24000 = 1 × 2400 × (x-10)
10 = x - 10
20 °C = x
Jadi suhu akhir alkohol adalah 20 °C
2 5 2
2014-02-14T15:42:53+07:00
Q = m.c.Δt
24 KJ = 1 kg. 2.400 J/kg°c. Δt
 \frac{24.000 J}{2.400 J/kg°C . 1 kg} = Δt
10°C = Δt
10°C = t₂ - t₁
10°C = t₂ - 10°C
t₂ = 10°C +10°C
t₂ = 20°C
2 5 2