Jawabanmu

2014-02-15T10:40:35+07:00
[OH] =√kw/ka.1
       = √10^-14/3,3.10^-4.1
       = √10^-10/3,3
        = √1/3,3  .  10^-5
[OH]=10^-14/3,3*10^-4
hidrolisis...

[OH^-] = AKAR Kw.M/Ka = akar 10^-14 . 1/ 3,3x10^-4 = akar 0,303x10^-10 = 0,55x10^5
maka Poh= - log OH^-
= - Log 5,5x10^-4
= 4-log 5,5
PH=14-Poh
= 14 - (4-log 5,5)
=10 + log 5,5