Jawabanmu

2014-08-23T11:47:54+07:00
Dikerjakan depan dan belakang dulu
 \frac{4}{ \sqrt{3+ \sqrt{2} } }+  \frac{5}{ \sqrt{3- \sqrt{2} } }= \\  \\ \frac{4. \sqrt{3- \sqrt{2} }+5. \sqrt{3+ \sqrt{2} }  }{3- \sqrt{2} }-  \frac{3}{ \sqrt{2-1} }   \\  \\  \frac{4. \sqrt{3- \sqrt{2} }. \sqrt{2-1}+5 \sqrt{3+ \sqrt{2} }. \sqrt{2-1}-3 . (3- \sqrt{2}     }{3. \sqrt{2-1}-2+ \sqrt{2}  } \\  \\     \frac{12-4 \sqrt{2}+15+5 \sqrt{2}-9+3 \sqrt{2}   }{1+ \sqrt{2} }  \\  \\  \frac{18+4 \sqrt{2} }{1+ \sqrt{2} } \\  \\ \frac{18+4 \sqrt{2} }{1+ \sqrt{2} } .  \frac{1- \sqrt{2} }{1- \sqrt{2} }
hasil akhirnya (10-14akar2)/-1 = 14 akar 2 -10
itu seharusnya akar 2 dikali akar 2 = 2 (tp makasih sebelumnya