Jawabanmu

2014-08-23T00:50:05+07:00
No 6
(x^-1.y)^(1/2)•(y^-1.z)^(1/2)•(z^-1.x)^(1/2)
= x^(-1/2) • y^(1/2) • y^(-1/2) • z^(1/2) • z^(-1/2) • x^(1/2)
= xyz