Jawabanmu

2014-08-21T20:52:47+07:00
 \frac{ (2^{n+2})^{2}-2^{2}(2^{2}n)}{2^{n}(2^{n+2})}
 \frac{(2^{n+2})(2^{n+2})-4(4n) }{2^{n}(2^{n+2})}
( 2^{n+2})-8 }  = (2^{n})(2^{2})-8 = 8^{n}-8

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