Jawabanmu

Jawaban paling cerdas!
2014-08-20T23:44:41+07:00
4^2^x^-^3+16^x^-^1= \frac{5}{64}
4^2^x^-^3+4^2^x^-^2= \frac{5}{64}
4^2^x(4^-^3+4^-^2)= \frac{5}{64}
4^2^x( \frac{1}{64} + \frac{1}{16} )= \frac{5}{64}
4^2^x( \frac{1+4}{64})= \frac{5}{64}
4^2^x( \frac{5}{64})= \frac{5}{64}

dari persamaan diatas coret 5/64 di kedua sisi, sehingga didapat
4^2^x= 1
x=0