Jawabanmu

2014-08-20T19:35:45+07:00
a = 3 + \sqrt6 \\ b = 3 - \sqrt6

a^2 = (3 + \sqrt6)^2 = (3)^2 + 2(3)(\sqrt6) + (\sqrt6)^2 = 9 + 6\sqrt6 + 6 = 15 + 6\sqrt6

b^2 = (3 - \sqrt6)^2 = (3)^2 + 2(3)(-\sqrt6) + (-\sqrt6)^2 = 9 - 6\sqrt6 + 6 = 15 - 6\sqrt6

ab = (3 + \sqrt6)(3 - \sqrt6) = 3^2 - (\sqrt6)^2 = 9 - 6 = 3

a^2 + b^2 - 6ab \\ = 15 + \sqrt{6} + 15 - \sqrt{6} - 6.3 \\ = 30 - 18 \\ = 12


terimakasih, jawaban kaka sangat membantu