Jawabanmu

2014-08-20T16:45:03+07:00

x + y ≤ 50
2y ≤ x + 40
x ≥ 0
y ≥ 0

x ≤ 50 - y

Jadi 2y ≤ 50 - y + 40
3y ≤ 90
y ≤ 30

x ≤ 50 - 30
x ≤ 20

Nilai maksimum 3x + 5y = 3.(20) + 5.(30) = 60 + 150 = 210

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