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2014-02-13T08:33:09+07:00
[H2PO4-] = 0,1 M X 50mL = 5mmol
[HPO4^2-] = 0,2 x 100ml = 20mmol

[H+] = Ka x [HA] / [A]
= 10^-5 x 5mmol / 20mmol
= 10^-5 x 0,25
= 25 x 10^-7

pH = - log [H+]
= - log 25 x 10^-7
= 7 - log 25
= 7- 1,39
= 5, 61
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