Jawabanmu

2014-08-19T09:30:30+07:00
Anggap log 2 = 0,3
[H⁺] = 2 × 10⁻²
pH = -log[H⁺]
= -log(2 × 10⁻²)
= -(log 2 + log 10⁻²)
= -(log 2 - 2 log 10)
= 2 log 10 - log 2
= 2 - 0,3 = 1,7