Jawabanmu

2014-08-17T14:36:51+07:00
\frac{3p^{3}.q.(-3)^{4}.4q^{2}}{(-2p)^{2}.(-3p)^{3}.p} \\ =\frac{3p^{3}.q.(3)^{4}.4q^{2}}{2^{2}.p^{2}.(-3)^{3}.p^{3}.p} \\ =\frac{3^{5}.2^{2}p^{3}.q^{3}}{2^{2}.(-3)^{3}.p^{6}} \\ =\frac{3^{5}.p^{3}.q^{3}}{-(3)^{3}.p^{6}}  \\ =-\frac{3^{2}.q^{3}}{p^{3}}
selanjutnya p dan q disubstitusikan ke persamaan tersebut menjadi
-\frac{3^{2}.6^{3}}{4^{3}} \\ -\frac{3^{2}.2^{3}.3^{3}}{2^{6}} \\ -\frac{3^{5}}{2^{3}} \\ -\frac{243}{8}
semoga dapat membantu.