Jawabanmu

2014-08-17T11:08:30+07:00
=(abc)^4 x 3/(bc)^3 x b^3/27.a^5
=a^4 x b^4 x c^4 x 1/b^3.c^3 x b^3/9a^5
= b¹ x c¹ x b³ per 9a
= b
⁴ x c per 9a





2014-08-17T11:15:51+07:00
(axbxc)^4 x 3 / (bxc)^3 x b^3 / 27a^5
= ( a^4 x b^4 x c^4 ) x 3 (b^3 x c^3) x b^3 / 27a^5
= (a^4-5 x b^4-3+3 x c^4-3 ) x 3 / 27
= (a^-1 x b^4 x c^1) 1/ 9
= b^4 x c / 9a